Question

$\frac{20x^2-10xy}{4x^2-y^2}$
нужно сократить дробь

Answer 1

$\displaystyle \frac{20x^2-10xy}{4x^2-y^2}=\frac{10x(2x-y)}{(2x+y)(2x-y)}=\frac{10x}{2x+y}$