Question

решите пж дам много балов

Answer 1

$1)\; \; 0,44=\frac{44}{100}=\frac{99}{225}\; ;\; \; 0,8=\frac{8}{10}=\frac{4}{5}=\frac{180}{225}\; ;\\\\\frac{2}{5}=\frac{90}{225}\; ;\; \; \frac{4}{9}=\frac{100}{225}\\\\\frac{180}{225}>\frac{100}{225}>\frac{99}{225}>\frac{90}{225}\; \; \Rightarrow \; \; min=\frac{90}{225}=\frac{2}{5}=0,4\\\\Otvet:\; \#3.\\\\2)\; \; \frac{1}{16}<\frac{1}{15}\; ;\; \; -\frac{1}{16}>-\frac{1}{15}\; ;\; \; -\frac{1}{15}<-\frac{1}{16}\; ;\; \; -\frac{1}{15}<\frac{1}{16}\; .\\\\Otvet:\; \; \#2.\\\\3)\; \; \frac{0,3\cdot 0,25}{0,45}=\frac{0,3\cdot 25}{45}=\frac{0,3\cdot 5}{9}=\frac{3\cdot 5}{90}=\frac{1}{6}$

$4)\; \; \frac{2,37}{1,15\cdot 0,18}=2,37:(1,15\cdot 0,18)=(2,37:1,15):0,18\\\\Otvet:\; \; \#1\; ,\; \#4\; .\\\\5)\; \; a=-2\; ,\; x=-0,2\\\\\frac{(a+x)(a-x)}{ax}=\frac{a^2-x^2}{ax}=\frac{(-2)^2-(-0,2)^2}{2\cdot 0,2}=\frac{4-0,04}{0,4}=\frac{3,96}{0,4}=\frac{396}{40}=9,9\\\\6)\; \; a\approx -0,4\\\\a)\; \; \frac{1}{a}=\frac{1}{-0,4}=-\frac{10}{4}=-2,5<-1\; \; \to \; \; \frac{1}{a}<-1\; \; verno\\\\b)\; \; -\frac{1}{a}=-\frac{1}{-0,4}=\frac{10}{4}=2,5>1\; \; \to \; \; -\frac{1}{a}>1\; \; verno$

$c)\; \; \frac{1}{a}=-\frac{10}{4}=-\frac{5}{2}=-2,5<-0,4\; \; \to \; \; \frac{1}{a}<a\; \; verno\\\\d)\; \; -\frac{1}{a}=\frac{10}{4}=\frac{5}{2}=2,5>-0,4\; \; \to \; \; -\frac{1}{a}<a\; \; neverno\\\\Otvet:\; \; \#4.$