Question

Найдите значения функции y=g(x) в заданных точках. е)g(x)=3- cos x/2 ;x1=0;x2=x/3;x3=-п

Answer 1

$g(x)=3-Cos\frac{x}{2}\\\\g(0)=3-Cos\frac{0}{2} =3-Cos0=3-1=2\\\\g(\frac{\pi }{3})= 3-Cos\frac{\frac{\pi }{3} }{2}=3-Cos\frac{\pi }{6}=3-\frac{\sqrt{3} }{2} =\frac{6-\sqrt{3} }{2} \\\\ g(-\pi )=3-Cos(-\frac{\pi }{2})=3-Cos\frac{\pi }{2} =3-0=3$