Question

0,8(х+2)=1,92; 3,6+5у=7(1,2-у) Допоможіть будь ласка!

Answer 1

$0.8(x + 2) = 1.92 \\ 0.8x + 1.6 = 1.92 \\ 0.8x = 1.92 - 1.6 \\ 0.8x = 0.32 \\ x = 0.32 \div 0.8 \\ x = 3.2 \div 8 \\ x = 0.4$
$3.6 + 5y = 7(1.2 - y) \\ 3.6 + 5y = 8.4 - 7y \\ 5y + 7y = 8.4 - 3.6 \\ 12y = 4.8 \\ y = 4.8 \div 12 \\ y = 0.4$

Answer 2

0,8(х+2) =1,92

х+2 = 1,92:0,8

х+2 = 2,4

х = 2,4-2

х = 0,4

3,6+5у = 7(1,2-у)

3,6+5у = 8,4 - 7у

5у+7у = 8,4 - 3,6

12у = 4,8

у = 4,8:12

у = 0,4