Question

математика помогите решить плз

Answer 1

$\sqrt[3]{ \sqrt[3]{81 {t}^{12} } } = \sqrt[9]{ {3}^{4} } \sqrt[3]{t^{4} } = \sqrt[9]{81} \sqrt[3]{ {t}^{4} }$
$\frac{ \sqrt[4]{32} }{ 6 \sqrt[4]{2} } = \frac{\sqrt[4]{16} }{6} = \frac{2}{6} = \frac{1}{3}$
$\sqrt[3]{54 \times 32} - \sqrt{8 \times 162} = \\ = \sqrt[3]{2 \times {3}^{3} \times {3}^{5} } - \sqrt{ {2}^{3} \times 2 \times {3}^{4} } = \\ \sqrt[3]{2 \times 3 ^{2} \times {3}^{6} } - \sqrt{ {2}^{4} \times {3}^{4} } = \\ = {3}^{2} \sqrt[3]{18} - 4 \times 9 = \\ = 9 \sqrt[3]{18} - 36$