Question

Разложите на множители:
y3+1
z3-27
64x3+1/8
0,008b6-125c3
x3-10x2+25x
36y3-60y2+72y
a2-b2+a-b
x2-10x+25-4y2

Answer 1

y³+1=(y+1)(y²+y+1)

z³-27= (z-3)(z²+27z+9)

64x³+1/8= (4x+1/2)(16x²-2x+1/4)

0,008b^6-125c³= (0,2b²-5c)(0,04b^4+b²c+25c²)

x³-10x²+25x= x(x-5)²= x(x-5)(x-5)

36y³-60y²+72y= 12y(3y²-5y+6)

a²-b²+a-b= (a-b)(a+b)+(a-b)= (a-b)(a+b+1)

x²-10x+25-4y²= (x-5)²-4y²= (x-5-2y)(x-5+2y)