Question

пожалуйста решите это

Answer 1

(2-i)/5 + (2+i)/10 = 2(2-i)/10 + (2+i)/10 = (4-2i+2+i)/10 = (6-i)/10

(2-i)/5 * (2+i)/10 = (4+2i-2i-i²)/50 = (2²-i²)/50 = (4-i²)/50

(2-i)/5 : (2+i)/10 = (2-i)/5 * 10/(2+i) = 2(2-i) / (2+i) = (4-2i)/(2+i)