Question

Решить систему уравнений x^2+y^2=5 x+y=3

Answer 1

$\left \{ {{x^2+y^2=5} \atop {x+y=3}} \right. \; \left \{ {{x^2+(3-x)^2=5} \atop {y=3-x}} \right. \; \left \{ {{2x^2-6x+4=0} \atop {y=3-x}} \right. \; \left \{ {{x^2-3x+2=0} \atop {y=3-x}} \right. \\\\\left \{ {{x_1=1\; ,\; x_2=2\; (teor.\; Vieta)} \atop {y=3-x\qquad \qquad \qquad }} \right. \; \left \{ {{x_1=1\; ,\; x_2=2} \atop {y_1=2\; ,\; y_2=1}} \right. \\\\Otvet:\; \; (1,2)\; ,\; (2,1)\;.$