Question

Срочно!!!!! 9 класс!!!!!

Answer 1

$\frac{(5 {x}^{ - 3}y) ^{ - 3} \times 25 {x}^{2} }{x {y}^{ - 4} } = \frac{25 {x}^{2} }{(5 {x}^{ - 3} y) ^{ 3}x {y}^{ - 4} } = \frac{25 {x}^{2} }{125 {x}^{ - 9} {y}^{3} x {y}^{ - 4} } = \frac{ {x}^{2 - ( - 9) - 1}}{5 {y}^{3 - 4} } = \frac{ {x}^{10}y }{5}$