Question

разложите на множители 6x2+5x+1

Answer 1

6x² + 5x + 1 = 0

D = 5² - 4 * 6 * 1 = 25 - 24 = 1

$x_{1} =\frac{-5+1}{12} =-\frac{4}{12} =-\frac{1}{3}\\\\x_{2} =\frac{-5-1}{12}=-\frac{6}{12}=-0,5\\\\\\6x^{2} +5x+1=6(x+\frac{1}{3})(x+0,5)$

Answer 2

6x² +3x+2x+1=0

3x(2x+1)+2x+1=0

(2x+1)(3x+1)=0

2x+1=0
3x+1=0

x=-1/2
x=-1/3

x1=-0,5
x2=-1/3