Question

${x}^{3} - 2 {x}^{2} - 5x + 6 = 0$
помогите решить

Answer 1

x³-x²-x²-6x+x+6=0

x²(x-1)-6(x-1)-x(x-1)=0

(x-1)(x²-6-x)=0

x1=1

x²-x-6=0

D= 1+24=25

x2= (1+5)/2= 3

x3= (1-5)/2= -2

Ответ: x1= 1,  x2= 3,  x3= -2