Question

(√2-√3)(5+√6)+√27/2√3+2√2-2=

Answer 1

$(\sqrt{2} -\sqrt{3})(5+\sqrt{6})+\frac{\sqrt{27} }{2\sqrt{3}}+2\sqrt{2}-2=5\sqrt{2} +\sqrt{12}-5\sqrt{3} -\sqrt{18}+\frac{\sqrt{9*3} }{2\sqrt{3}}+2\sqrt{2}-2=5\sqrt{2}+2\sqrt{3}-5\sqrt{3}-3\sqrt{2}+1,5+2\sqrt{2}-2=4\sqrt{2}-3\sqrt{3}-0,5$