Question

Ради Бога, решите это уравнение!
3(целых)1/4 + 1/2у + 1(целая)1/3 + 5/6у = 5(целых) 11/12

Answer 1

$\displaystyle \tt 3\frac{1}{4}+\frac{1}{2}y+1\frac{1}{3}+\frac{5}{6}y=5\frac{11}{12}\\\\\frac{3}{6}y+\frac{5}{6}y=\frac{71}{12}-\frac{39}{12}-\frac{16}{12}\\\\\frac{8}{6}y=\frac{16}{12}\\\\y=\frac{16}{12}*\frac{6}{8}\\\\y=1$

Ответ: {1}

Answer 2

$3 \frac{1}{4} + \frac{1}{2} y + 1 \frac{1}{3} + \frac{5}{6} y = 5 \frac{11}{12} \\ ( \frac{1}{2} + \frac{5}{6} )y = \\ \\ = \frac{5 \times 12 + 11}{12} - \frac{3 \times 4 + 1}{4} - \frac{4}{3} \\ \\ \frac{8}{6} y = \frac{71 - 13 \times 3 - 4 \times 4}{12}$
16y=71-39-16
16y=16
y=1