Question

помогите решить пример 8 целых 1\2 :(9,25-5\6:3целых1\3)+13целых1\2:0,9=?

Answer 1

$8 \frac{1}{2} \div (9.25 - \frac{5}{6} \div 3 \frac{1}{3}) + 13 \times \frac{1}{2} \div 0.9 = 15 \frac{17}{18} \\ 1) - \frac{5}{6} \div \frac{10}{3} = - \frac{5}{6} \times \frac{3}{10} = - \frac{ 1}{4} \\ 2)9.25 - - \frac{1}{4} = 9.25 - 0.25 = 9 \\ 3)8 \frac{1}{2} \div 9 = \frac{17}{2} \div \frac{9}{1} = \frac{17}{2} \times \frac{1}{9} = \frac{17}{18} \\ 4)13 \times \frac{1}{2} = 13 \frac{1}{2} \\ 5)13 \frac{1}{2} \div 0.9 = \frac{27}{2} \times \frac{10}{9} = 15 \\ 6) \frac{17}{18} + 15 = 15 \frac{17}{18}$