Question

Решите плиз очень нужно.

Answer 1

$\frac{ {x}^{2} }{x - 3} + \frac{18 + 2 {x}^{2} }{ {x}^{2} + 3x + 9} + \frac{3x( {x}^{2} + x + 15)}{27 - {x}^{3} } = \frac{ {x}^{2} }{x - 3} + \frac{18 + 2 {x}^{2} }{ {x}^{2} + 3x + 9} - \frac{3x( {x}^{2} + x + 15)}{ {x}^{3} - 27 } = \frac{ {x}^{2} ( {x}^{2} + 3x + 9)}{(x - 3)( {x}^{2} + 3x + 9)} + \frac{(18 + 2 {x}^{2})(x - 3) }{( x - 3)( {x}^{2} + 3x + 9) } - \frac{3x( {x}^{2} + x + 15)}{ (x - 3)( {x}^{2} + 3x + 9)} = \frac{ {x}^{4} + 3 {x}^{3} + 9 {x}^{2} + 18x + 2 {x}^{3} - 54 - 6 {x}^{2} - 3 {x}^{3} - 3 {x}^{2} - 45x }{(x - 3)( {x}^{2} + 3x + 9) } = \frac{ {x}^{4} + 2 {x}^{3} - 27x - 54 }{?} = \frac{ {x}^{3} (x + 2) - 27(x + 2)}{(x - 3)( {x}^{2} + 3x + 9)} = \frac{(x + 2)( {x}^{3} - 27)}{ {x}^{3} - 27} = x + 2$