Question

sin(7pi/4) *cos(5pi/3) *tg(7pi/6)*ctg(4pi/3)

Answer 1

$\sin(7\pi/4)\cos(5\pi/3)tg(7\pi/6)ctg(4\pi/3)=-\frac{\sqrt{2}}{2}\cdot0.5\cdot\frac{\sqrt{3}}{3}\cdot\frac{\sqrt{3}}{3}=-\frac{\sqrt{2}}{12}$