Question

Как сократить дробь а²-10а-24÷a³+8

Answer 1

$\frac{ {a}^{2} - 10a - 24 }{ {a}^{3} + 8 } = \frac{ {a}^{2} + 2a - 12a - 24 }{(a + 2)( {a}^{2} - 2a + 4) } = \frac{a(a + 2) - 12(a + 2)}{(a + 2)( {a}^{2} - 2a + 4) } = \frac{(a + 2)(a - 12)}{(a + 2)( {a}^{2} - 2a + 4) } = \frac{a - 12}{ {a}^{2} - 2a + 4}$

Answer 2

a² +2a-12a-24/(a+2)(a²-2a+4)

= a(a+2)-12(a+2)/(a+2)(a²-2a+4)

= (a+2)(a-12)/(a+2)(a²-2a+4)

= a -12/a² -2a + 4