Question

Как решить уравнение (x-4)^2+x(4-x)=8

Answer 1

${(x - 4)}^{2} + x(4 - x) = 8 \\ {x}^{2} - 8x + 16 + 4x - {x}^{2} - 8 = 0 \\ 8 - 4x = 0 \\ 4x = 8 \\ x = 2$

Answer 2

x²-8x+16+4x-x²=8
-4x+16=8
-4x=8-16
-4x=-8
x=2