Question

Решить в 1.203 А,Е

Answer 1

$a) {( \sqrt{20} + \sqrt{5}) }^{2} = { \sqrt{20} }^{2} + 2 \sqrt{20 \times 5} + { \sqrt{5} }^{2} = 20 + 2 \sqrt{100} + 5 = 25 + 20 = 45 \\ e) {( \sqrt{0.18} + \sqrt{0.08} ) }^{2} = 0.18 + 2 \sqrt{0.0144} + 0.08 = 0.26 + 2 \times 0.12 = 0.26 + 0.24 = 0.5$

Answer 2

$(\sqrt{20}+\sqrt{5})^2=(\sqrt{4\cdot 5}+\sqrt{5})^2=(2\sqrt{5}+\sqrt{5})^2= (3\sqrt{5})^2=9\cdot 5=45$

$(\sqrt{0,18}+\sqrt{0,08})^2=\left(\sqrt{\frac{9\cdot 2}{100}}+\sqrt{\frac{4\cdot 2}{100}}\right)^2=\left(\frac{3\sqrt{2}}{10}+\frac{2\sqrt{2}}{10}\right)^2= \left(\frac{5\sqrt{2}}{10}\right)^2=$

$=\left(\frac{\sqrt{2}}{2}\right)^2=\frac{2}{4}=\frac{1}{2}=0,5$

Ответ: а) 45; е) 0,5