Question

разложить на множители: x-4y+x²-16y² ; ab⁶-ab⁴-b⁶+b⁴

Answer 1

$x - 4y + {x}^{2} - 16 {y}^{2} = x(1 + x) - 4y(1 + 4y) \\ \\ a {b}^{6} - a {b}^{4} - {b}^{6} + {b}^{4} = {b}^{6} (a - 1) - {b}^{4} (a - 1) = (a - 1)( {b}^{6} - {b}^{4} )=(a - 1)( {b}^{3} - {b}^{2})( {b}^{3} + {b}^{2} )$