Question

Разложите на множители: (x^2+1)^2-4x^2

Answer 1

$(a {}^{2} + 4) {}^{2} - 16a {}^{2} \\ (a {}^{2} + 4 - 4a) \times (a {}^{2} + 4 + 4a) \\ (a {}^{2} - 4a + 4) \times (a {}^{2} + 4a + 4) \\ (a - 2) {}^{2} \times (a + 2) {}^{2} \\ \\ 2)9 - (2c - 1) {}^{2} \\ (3 - 2c - 1)) \times (3 + (2c - 1)) \\ (3 - 2c + 1) \times (3 + 2c - 1) \\ (4 - 2c) \times (2 + 2c) \\ 2(2 - c) \times 2(1 + c) \\ 2 \times 2(2 - c) \times (1 + c) \\ 4(2 - c) \times (1 + c)$