Question

2 в степени $^{x^{2} -5x+6.5 }$  и =$\sqrt{2}$

Answer 1

2^x²-5x+6,5=√2

2^x²-5x+6,5=2^1/2

x²-5x+6,5=1/2

x²-5x+13/2=1/2

2x²-10x+13=1

2x²-10x+13-1=0

2x²-10x+12=0

x²-5x+6=0

x=-(-5)±√(-5)²-4*1*6/2*1

x=5±√25-24/2

x=5±√1/2

x=5±1/2

x=5+1/2

x=5-1/2

x=3
x=2

x1=2
x2=3