Question

Помогите , даю 35 баллов

Answer 1

$\frac{(-11 \frac 2 3 + 8.6)\times 4.5 - 4.5}{(5 \frac 2 5 + 8.12 - 3 \frac 3 {10} - 7.75):(-2.695)} \\ \\ \frac{(-11 \frac 2 3 + 8.6)\times 4.5 - 4.5}{(5.4 + 8.12 - 3.3 - 7.75):(-2.695)} \\ \\ \frac{(-11 \frac 2 3 + 8.6)\times 4.5 - 4.5}{(2.47):(-2.695)} \\ \\ \frac{(-11 \frac 2 3 + 8.6 - 1)\times 4.5}{(2.47):(-2.695)}$

$\frac{(-11 \frac 2 3 + 7.6)\times 4.5}{(2.47):(-2.695)} \\ \\\frac{(\frac {-61}{15})\times 4.5}{(2.47):(-2.695)} \\ \\ \frac{(\frac {-61}{15})\times(\frac {45} {10})}{(2.47):(-2.695)} \\ \\ \frac{(\frac {-61}{1})\times(\frac {3} {10})}{(2.47):(-2.695)} \\ \\ \frac{\frac{-183}{10}}{2.47 : (-2.695)} \\ \\ \frac{-18.3}{2.47 : (-2.695)} \\ \\ \frac{98637}{4940}$

Answer 2

$\frac{( - 11 \frac{2}{3} + 8.6) \times 4.5 - 4.5 }{(5 \frac{2}{5} + 8.12 - 3 \frac{3}{10} - 7.75 ) \div ( - 2.695)} = \\ = \frac{4.5 \times ( - 11 \frac{2}{3} + 8 \frac{3}{5} - 1 ) \times ( - 2.695)}{5.4 + 8.12 - 3.3 - 7.75} = \\ = \frac{ - 12.1275 \times ( - 4 + \frac{3}{5} - \frac{2}{3} )}{2.47} = \\ = \frac{12.1275 \times 4 \frac{1}{15} }{2.47} = \frac{12.1275 \times 61}{15 \times 2.47} = \\ = \frac{0.8085 \times 61}{2.47} = \frac{49.3185}{2.47} = \frac{493185}{24700} = \\ = \frac{3 \times 5 \times {7}^{2} \times11 \times61 }{ {2}^{2} \times {5}^{2} \times 13 \times 19} = \\ = \frac{98637}{4940} = 19 \frac{4777}{4940}$