Question

(y+7)^2
(2x+3)^2
(x-5y)^2
(X+5)^2
(4-x)^2
(3y-x)^2
(6x+2)^2
возвести в квадрат

Answer 1

$(y+7)^2=y^2+14y+49\\(2x+3)^2=4x^2+12x+9\\(x-5y)^2=x^2-10xy+25y^2\\(x+5)^2=x^2+10x+25\\(4-x)^2=16-8x+x^2=x^2-8x+16\\(3y-x)^2=9y^2-6xy+x^2\\(6x+2)^2=36x^2+24x+4$