Question

СРОЧНО ПОМОГИТЕ, ПОЖАЛУЙСТА!))

Answer 1

$\displaystyle\tt 1) \ \frac{49}{(3\sqrt{7})^2}=\frac{7^2}{3^2\cdot7}=\frac{7}{9}\\\\\\ 2) \ \frac{8x^2}{5-x}\cdot\frac{x^2-25}{16x^4}=\frac{1}{-(x-5)}\cdot\frac{(x-5)(x+5)}{2x^2}=-\frac{x+5}{2x^2}$