Question

Решите неравенство. 13(2х+1)-8 (знак меньше равно) 3-4х

Answer 1

$13(2x+1)-8\leq 3-4x$

$26x+13-8\leq 3-4x$

$30x\leq 3-13+8$

$30x\leq -2$

$x\leq -\frac{2}{30}$

Answer 2

13(2x+1)-8≤3-4x

26x+13-8≤ 3-4x

26x+4x≤8-13+3

30x≤-2

x≤-15

x∈(-∞;-15]