Question

Сумма корней уравнения 1/x^2-3/x-4=0

Answer 1

$\frac{1}{x^2}-\frac{3}{x}-4=\frac{-4x^2-3x+1}{x^2}=\frac{4x^2+3x-1}{x^2}=0$

$4x^2+3x-1=0$

$x=-1; \ x=\frac{1}{4}; \ \ 1/4-1=-3/4$