Question

ТОЛЬКО 2 ЗАДАНИЕ!!!!!!!!!!!!!!!!!!!!!!!!! СРОЧНО! !!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

1.Найдите значения выражения:

1) $\frac{4x+y}{5x-4y}$ = $\frac{4*(-4)+2}{5*(-4)-4*2}$ = $\frac {-16+2}{-20-8}$ = $\frac {-14}{-28}$   = $\frac {1}{2}$  

2)$\frac{a^{2}-4a}{7a-1}$ =$\frac{0.2^{2}-4*0.2}{7*0.2-0.2}$  = $\frac{0.04-0,8}{1.4-0.2}$ = $\frac{-0.76}{1.2}$