Question

(3-4x)^2-1/3(3x-2)(3x+2)=13x^2-2/3
решите уравнение пожалуйста

Answer 1

$9 - 24x + 16 {x}^{2} - \frac{1}{3} (9 {x}^{2} - 4) =13 {x}^{2} - \frac{2}{3} \\ \\ 9 - 24x + 16 {x}^{2} + 13 {x}^{2} = 13 {x}^{2} - \frac{2}{3} \\ \\ \frac{31}{3} - 24x = - \frac{2}{3} \\ \\ 31 - 72x = - 2 \\ \\ - 72x = - 2 - 31 \\ \\ - 72x = - 33 \\ \\ x = \frac{11}{24}$