Question

помогите решить
(0.2х-10у)²

Answer 1

$(0.2x - 10y) {}^{2} \\ \\ ( \frac{1}{5} x - 10y) {}^{2} \\ \\ ( \frac{1}{5} x) {}^{2} - 2 \frac{1}{5} x \times 10y + (10y) { }^{2} \\ \\ \frac{1}{25} x {}^{2} - 2 \frac{1}{5} x \times 10 + (10y) {}^{2} \\ \\ \frac{1}{25} x {}^{2} - 4xy + (10y) {}^{2} \\ \\ \frac{1}{25} x { }^{2} - 4xy + 100y {}^{2}$