Question

x^4+3x^2-4=0 Помогите решить пожалуйста!

Answer 1

$x {}^{4} + 3 {x}^{2} - 4 = 0 \\ {t}^{2} + 3t - 4 = 0 \\ t = 1 \\ t = - 4 \\ \\ {x}^{2} = 1 \\ {x}^{2} = - 4 \\ \\ x = 1 \\ x = - 1 \\ \\ x1 = - 1 \\ x2 = 1$