Question

помогите решить дз вот 3 столбик надо решить в) е) и) м)

Answer 1

в)
$... = ( {2}^{4} )^{ - 3} \div {2}^{ - 6} = {2}^{ - 12} \div {2}^{ - 6} = {2}^{ - 12 - ( - 6)} = {2}^{ - 12 + 6} = {2}^{ - 6}$
е)
$... = ( {4}^{ - 12} \times {2}^{25} ) ^{ - 5} =( ( {2}^{2} )^{ - 12} \times {2}^{25} )^{ - 5} = ( {2}^{ - 24} \times {2}^{25} )^{ - 5} = {2}^{ - 5}$
и) .

$\frac{( {6}^{ - 2})^{3} }{( {6}^{2}) ^{ - 2} } = \frac{ {6}^{ - 6} }{ {6}^{ - 4} } = {6}^{ - 6 - ( - 4)} = {6}^{ - 6 + 4} = {6}^{ - 2} = \frac{1}{36}$
м) .
$... = \frac{ {0.5}^{2} }{( {0.5}^{3} ) ^{ - 3} \times {4}^{ - 5} } = \frac{ {0.5}^{2} \times {4}^{5} }{ {0.5}^{ - 9} } = {0.5}^{2} \times {0.5}^{9} \times {4}^{5} = {0.5}^{7} \times {4}^{5} = ( \frac{1}{2})^{7} \times ( {2}^{2}) ^{5} = \frac{ {2}^{10} }{ {2}^{7} } = {2}^{10 - 7} = {2}^{3} = 8$