Question

x²-25=
16-c²=
a²-6a+9=
x²+8x+16=
x³-8=
b³+27=
решите пожалуйста

Answer 1

${x}^{2} - 25 = (x - 5)(x + 5) \\ 16 - {c}^{2} = (4 - c)(4 + c) \\ a {}^{2} - 6a + 9 = (a - 3) {}^{2} \\ {x}^{2} + 8x + 16 = (x + 4) {}^{2} \\ {x}^{3} - 8 = (x - 2)(x {}^{2} + 2x + 4) \\ {b}^{3} + 27 = (b + 3)( {b}^{2} - 3b + 9)$