Question

как решить (с+2)(с-3)-(с-1)^2

Answer 1

${c}^{2} - 3c + 2c - 6 - ( {c}^{2} - 2c + 1) = \\ = {c}^{2} - 3 + 2c - 6 - {c}^{2} + 2c - 1 = c - 7$