Question

4y^3+y=4y^2 решение.

Answer 1

$4 {y}^{3} + y = 4 {y}^{2} \\ 4 {y}^{3} + y - 4 {y}^{2} = 0 \\ y \times (4 {y}^{2} + 1 - 4y) = 0 \\ y \times (4 {y}^{2} - 4y + 1) = 0 \\ y \times (2y - 1) {}^{2} = 0 \\ \\ y = 0 \\ (2y - 1) {}^{2} = 0 \\ \\ y = 0 \\ y = \frac{1}{2} \\ \\ - - - - - - - \\ \\ y1 = 0 \\ y2 = 0.5$