Question

помогите решить (°°°°°°°°°°°°°°°°°)

Answer 1

$\displaystyle \tt\frac{m}{m-3}+\frac{3m}{(3-m)^{2}}=\frac{3m}{(3-m)^{2}}-\frac{m}{3-m}=\frac{3m-m(3-m)}{(3-m)^{2}}=\\\\\\=\frac{m^{2}}{(3-m)^{2}}=\bigg(\frac{m}{3-m}\bigg)^{2}$