Question

решите пожалуйста
1) 6^x= √6
2)
$\sqrt[3]{128} = 2 {}^{3x}$

Answer 1

$1)6^{x}=6^{\frac{1}{2}} \\\\x=\frac{1}{2}$

$2)128^{\frac{1}{3}}=2^{3x}\\\\2^{\frac{7}{3}}=2^{3x}\\\\\frac{7}{3}=3x\\\\x=\frac{7}{9}$

Answer 2

${6}^{x} = \sqrt{6} \\ {6}^{x} = 6 {}^{ \frac{1}{2} } \\ x = 0.5 [tex] - - - - - \\ \sqrt[3]{128} = 2 {}^{3x} \\ 2 {}^{ \frac{7}{3} } = 2 {}^{3x} \\ 3x = \frac{7}{3} \\ x = \frac{7}{9}$