Question

sin4x-cos4x=-sin4x решите задачу

Answer 1

$\sin4x-\cos 4x=-\sin4x\\ \\ 2\sin4x-\cos 4x=0~~~|:\cos 4x\ne0\\ \\ 2tg4x=1\\ \\ tg4x=0.5\\ \\ 4x=arctg0.5+\pi n,n \in \mathbb{Z}\\ \\ \boxed{x=0.25arctg0.5+0.25\pi n,n \in \mathbb{Z}}$