Question

Решите систему неравенств
1>3z
4z-1>0

Answer 1

$3z-1<0;\ z-\frac{1}{3}<0;\ z<\frac{1}{3}$

$4z-1>0;\ z-\frac{1}{4}>0;\ z>\frac{1}{4}$

$\frac{1}{4}<z<\frac{1}{3}$