Question

27a^(3)-b^(3)\15a-5b решить

Answer 1

$\frac{27 {a}^{3} - {b}^{3} }{15a - 5b} = \frac{(3a - b)(9 {a}^{2} + 3ab + {b}^{2}) }{5(3a - b)} = \frac{9 { {a}^{2} + 3ab + {b}^{2} } }{5}$

Answer 2

$\frac{(3a - b) \times (9 {a}^{2} + 3ab + {b}^{2} ) }{5(3a - b)} = \frac{9 {a}^{2} + 3ab + {b}^{2} }{5}$