Question

Корень из 3,6*12,1 помогите дурашке)

Answer 1

$\displaystyle \tt\sqrt{3.6\cdot 12.1} = \sqrt{\frac{36}{10} \cdot \frac{121}{10} }=\sqrt{\frac{6^2\cdot11^2}{10^2}}=\sqrt{\bigg(\frac{6\cdot11}{10}\bigg)^2}=\sqrt{\bigg(\frac{66}{10}\bigg)^2}= \\\\\\ =\frac{66}{10}=6.6$