Question

помогите решить. нужно решить все 3 желательно подробнее

Answer 1

1)
$\frac{2ax}{3x - y} + \frac{y + 2}{3x - y} = \frac{2ax + y + 2}{3x - y}$
2)
$\frac{ {a}^{2} }{ {(a - b)}^{2} } - \frac{2ab - {b}^{2} }{ {(a - b)}^{2} } = \frac{ {a}^{2} - (2ab - {b}^{2} ) }{ {(a - b)}^{2} } = \frac{ {a}^{2} - 2ab + {b}^{2} }{ {(a - b)}^{2} } = \frac{ {(a - b)}^{2} }{ {(a - b)}^{2} } = 1$
3)
$\frac{ {x}^{2} }{ {(x + y)}^{2} } - \frac{ {y}^{2} - 2xy}{ {(x + y)}^{2} } = \frac{ {x}^{2} - ( {y}^{2} - 2xy)}{ {(x + y)}^{2} } = \frac{ {x}^{2} - {y}^{2} + 2xy }{ {(x + y)}^{2} }$