Question

Решите цепочку пожалуйста 7 класс

Answer 1

Решение во вложении:

Answer 2

task/29376936#

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1) (4m⁴a/6x²)*(2x²/4m³a²) =(4m⁴a*2x²) / (6x²*4m³a²) = m / 3a .

2) (m / 3a) : (10+2a) / 6a² = (m / 3a) * 6a² / (10+2a) =(m*6a²) / 3a(10+2a) = m*2a/(10+2a) =m*2a/ 2(5+a) =ma/(5+a) .

3) ma/(5+a) *(a²-25)/2m² =ma/(5+a) *(a-5)(a+5) /2m² =ma*(a-5)(a+5)/(5+a)2m²=

a(a-5)/2m.

4) ( a(a-5)/2m ) : (a²-10a+25)/6m =a(a-5)6m / 2m(a-5)² = 3a / (a-5).