Question

3(d^1/13)^6 + 4d^2 при d=3

Answer 1

$3 \ \cdotp \bigg(\dfrac{d^{1}}{13} \bigg)^{6} + 4d^{2} = \dfrac{3d^{6}}{13^{6}} + 4d^{2}$

При $d = 3$:

$\dfrac{3 \ \cdotp 3^{6}}{13^{6}} + 4 \ \cdotp 3^{2} = \dfrac{3^{7}}{13^{6}} + 36 = \dfrac{2187}{13^{6}} + 36 \approx 36$