Question

помогите пожалуйста))

Answer 1

$( \frac{2}{5a - 25} - \frac{4}{ {a}^{2} - 25 } - \frac{1}{5a + 25} ) \times ( {a}^{2} + 10a + 25) = ( \frac{2}{5(a - 5)} - \frac{4}{(a - 5)(a + 5)} - \frac{1}{5(a + 5)} ) \times {(a + 5)}^{2} = \frac{2(a + 5) - 4 \times 5 - 1 \times (a - 5)}{5(a - 5)(a + 5)} \times {(a + 5)}^{2} = \frac{2a + 10- 20 - a + 5}{5(a - 5)(a + 5)} \times {(a + 5)}^{2} = \frac{a - 5}{5(a - 5)} \times (a + 5) = \frac{a + 5}{5}$

Answer 2

$(\frac{2}{5a-25}-\frac{4}{a^2-25}-\frac{1}{5a+25} )(a^2+10a+25)=$

$=(\frac{2}{5(a-5)}-\frac{4}{(a-5)(a+5)}-\frac{1}{5(a+5)}})(a+5)^2=$

$=(\frac{2(a-5)(a+5)-4*5(a-5)}{5(a-5)(a-5)(a+5)} -\frac{1}{5(a+5)} )(a+5)^2=$

$=(\frac{2(a+5)-20}{5(a-5)(a+5)}-\frac{1}{5(a+5)})(a+5)^2=$

$=(\frac{2a-10}{5(a-5)(a+5)}-\frac{1}{5(a+5)})(a+5)^2=$

$=(\frac{2(a-5)}{5(a-5)(a+5)} -\frac{1}{5(a+5)})(a+5)^2=$

$=(\frac{2}{5(a+5)}-\frac{1}{5(a+5)})(a+5)^2=$

$=(\frac{2*5(a+5)-5(a+5)}{5(a+5)*5(a+5)} )(a+5)^2=$

$=\frac{2(a+5)^2}{5(a+5)} =\frac{2(a+5)}{5} =\frac{2}{5} a+2$ $=\frac{1}{5}a+1$