Question

Вычислите:
$\frac{ (2^{-3})^4 }{ 16^{-2} }$

Answer 1

$\frac{ {( {2}^{ - 3}) }^{4} }{ {16}^{ - 2} } = \frac{ {2}^{ - 3 \times 4} }{ {( {2}^{4}) }^{ - 2} } = \frac{ {2}^{ - 12} }{ {2}^{4 \times ( - 2)} } = \frac{ {2}^{ - 12} }{ {2}^{ - 8} } = {2}^{ - 12 - ( - 8)} = {2}^{ - 12 + 8} = {2}^{ - 4} = \frac{1}{ {2}^{4} } = \frac{1}{16}$

Answer 2

2^-12/2^-8=1/2^4=1/16