Question

помогите сроооочнооооо, пожалуйста!!!!!

Answer 1

${3}^{ {x}^{2} } \times {2}^{ {x}^{2} + 1 } = \frac{1}{3} \sqrt{ {36}^{ {x}^{4} - 19} } \\ {3}^{ {x}^{2} } \times {2}^{ {x}^{2} } \times 2 = \frac{1}{3} \times \sqrt{ {6}^{2( {x}^{4} - 19) } } \\ {6}^{ {x}^{2} } \times 2 = \frac{1}{3} \times {6}^{ {x}^{4} - 19} \\ {6}^{ {x}^{2} } = \frac{1}{6} \times {6}^{ {x}^{4} - 19} \\ {6}^{ {x}^{2} } = {6}^{ {x}^{4} - 19 - 1} \\ {6}^{ {x}^{2} } = {6}^{ {x}^{4} - 20 } \\ {x}^{2} = {x}^{4} - 20 \\ {x}^{4} - {x}^{2} - 20 = 0 \\ {x}^{2} = t. \: \: \: \: \: t \geqslant 0 \\ {t}^{2} - t - 20 = 0 \\ d = {b}^{2} - 4ac = 1 - 4 \times ( - 20) = 1 + 80 = 81 \\ t1 = \frac{1 + 9}{2} = 5 \\ t2 = \frac{1 - 9}{2} = - 4 \\ {x}^{2} = 5 \\ x = + - \sqrt{5} \\ 9 \times \sqrt{5} \times ( - \sqrt{5} ) = 9 \times ( - 5) = - 45$
Ответ: -45