Question

Помогите пожалуйста!!!! Для проверки надо срочно

Answer 1

$\frac{2}{cd}-\frac{3}{dk}=\frac{2k-3c}{cdk}\\\\\frac{a}{mp}+\frac{a}{mn}=\frac{an+ap}{mnp}=\frac{a(n+p)}{mnp}\\\\\frac{8}{a}-\frac{2}{ap}=\frac{8p-2}{ap}=\frac{2(4p-1)}{ap}\\\\\frac{2}{a}-\frac{1}{b}=\frac{2b-a}{ab}\\\\\frac{4}{3n}-\frac{3}{2m}+\frac{5m}{12}=\frac{4\cdot 4m-3\cdot 6n+5m\cdot mn}{12mn}=\frac{16m-18n+5m^2}{12mn}$

$\frac{4k}{15}-\frac{8}{3p}-\frac{2}{5k}=\frac{4k\cdot kp-8\cdot 5k-2\cdot 3p}{15kp}=\frac{2\cdot (2k^2p-20k-3p)}{15kp}$