Question

помогите пожалуйстаа
$\sqrt{19+6\sqrt{2}} -\sqrt{19-6\sqrt{2}}$

Answer 1

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$\sqrt{19 + 6 \sqrt{2} } - \sqrt{19 - 6 \sqrt{2} } = \\ = \sqrt{18 + 1 + 6 \sqrt{2} } - \sqrt{18 + 1 - 6 \sqrt{2} } = \\ = \sqrt{1 + 6 \sqrt{2} + 18 } - \sqrt{1 - 6 \sqrt{2} + 18 } = \\ = \sqrt{(1 + 3 \sqrt{2 })^{2} } - \sqrt{(1 - 3 \sqrt{2} )^{2} } = \\ = 1 + 3 \sqrt{2} - 3 \sqrt{2} + 1 = 2$
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Готово.
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Answer 2

Решение во вложении.