Question

Решите линейное уравнение пж

{4у=5х-1
{2х+6у=11

Answer 1

$\left \{ {{4y=5x-1} \atop {2x+6y=11}} \right.\; \left \{ {{5x-4y=1\; |\cdot 2} \atop {2x+6y=11\; |\cdot (-5)}} \right.\oplus \; \left \{ {{5x-4y=1} \atop {0\cdot x-38y=-53}} \right. \; \left \{ {{5x=4y+1} \atop {y=\frac{53}{38}=1\frac{15}{38}}} \right.\\\\5x=4\cdot \frac{53}{38}+1\; ,\; \; 5x= \frac{250}{38}\; ,\; \; x=\frac{250}{38}:5=\frac{250}{38\cdot 5}=\frac{50}{38}=\frac{25}{19}=1\frac{6}{19}\\\\Otvet:\; \; (1\frac{6}{19}\; ,\; 1\frac{15}{38})\; .$